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===Season 1=== |
===Season 1=== |
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| − | The Grey-Haired Man announces the arrival of [[Charlie Luciano]] and [[Frankie Yale]] while Rothstein plays pool in a large games room. ("[[The Ivory Tower]]") |
+ | The Grey-Haired Man announces the arrival of [[Charlie Luciano]] and [[Frankie Yale]] while Rothstein plays pool in a large games room. ("[[The Ivory Tower]]") |
Rothstein hands a letter to the Grey-Haired Man while on the phone with Luciano. ("[[Family Limitation]]") |
Rothstein hands a letter to the Grey-Haired Man while on the phone with Luciano. ("[[Family Limitation]]") |
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===Season 2=== |
===Season 2=== |
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| − | The Grey-Haired Man accompanies [[Arnold Rothstein|Rothstein]] when he mediates a meeting between [[Charlie Luciano]], [[Meyer Lansky]] and [[Joe Masserria]]. ("[[A Dangerous Maid]]") |
+ | The Grey-Haired Man accompanies [[Arnold Rothstein|Rothstein]] when he mediates a meeting between [[Charlie Luciano]], [[Meyer Lansky]] and [[Joe Masserria]]. ("[[A Dangerous Maid]]") |
He accompanies Rothstein to a meeting with his horse trainer [[Max Hirsch]]. ("[[Two Boats and a Lifeguard]]") In August 1921 he takes a phone call from [[Nucky Thompson]] as Rothstein meets with Luciano and Lansky to discuss becoming involved in importing and distributing heroin. ("[[To the Lost]]") |
He accompanies Rothstein to a meeting with his horse trainer [[Max Hirsch]]. ("[[Two Boats and a Lifeguard]]") In August 1921 he takes a phone call from [[Nucky Thompson]] as Rothstein meets with Luciano and Lansky to discuss becoming involved in importing and distributing heroin. ("[[To the Lost]]") |
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==Relationships== |
==Relationships== |
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| − | *[[Arnold Rothstein]] - Employer |
+ | *[[Arnold Rothstein]] - Employer |
*[[Charlie Luciano]] - Associate |
*[[Charlie Luciano]] - Associate |
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*[[Meyer Lansky]] - Associate |
*[[Meyer Lansky]] - Associate |
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| − | *[[Eddie Kessler]] - Associate |
+ | *[[Eddie Kessler]] - Associate |
| − | *[[Nucky Thompson]] - Associate |
+ | *[[Nucky Thompson]] - Associate |
==Appearances== |
==Appearances== |
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